Calculation formula and calculation guide for industrial chillers Industrial chillers have the ability to precisely control oil temperature, effectively reducing the deformation of the airport due to local overheating, and improving the processing accuracy of machine tools. Industrial chillers are equipped with unloading energy control devices, which can achieve multi-level and stepless energy adjustment; industrial chilled water The fully enclosed scroll refrigeration compressor has the advantages of high efficiency, low noise, low vibration and long life. In general, as a new type of air-cooled radiator, integrated air cooling is quick to install and good in heat dissipation. It will definitely have a certain position in today's society and even in the future radiator market. For manufacturers who like quiet installation, fast and advanced air-cooled platforms, the air-cooled integrated radiator is a very good choice.
Air-cooled industrial chillers The choice of industrial chillers, okmarts.com prompts the choice to include the following three points: 1. First of all, the temperature difference of the standard chiller is 5 degrees, (20 degrees drop 15 degrees), if a 10W chiller has a standard chiller flow rate of 3.5 cubic meters per hour. 2. Secondly, when you try this industrial chiller, you can’t just look at the flow of the chiller, but also what temperature you need. If the temperature you tried was dropped from 28 degrees to 7 degrees, if If you use a cold water machine with a large temperature difference, the hourly chilled water flow will be reduced from 3.5 cubic meters to more than one cubic meter. 3. If you want 3.5 cubic meters per hour, you have to choose a larger model. 4. Finally, when trying out an industrial chiller, it depends on whether you are cooling directly or indirectly. Direct cooling is to put water directly into the chiller, and the chilled water comes out directly to cool the product you need, so the effect will be better. some. 5. What about indirect cooling? For example, put water in a basin, put a small basin on top of the basin, and put the product to be cooled in the small basin. This effect will definitely be worse. When you choose the machine, you must consider this. All aspects of the problem are affected by the size.
Low temperature chiller If you want to choose an industrial chiller by calculation, you can refer to the following formula and calculation guide: 1. Calculate the calorific value by the temperature difference between the inlet and outlet of the cooling water (oil). Q = SH De F DT / 60Q: calorific value KW (note: the calorific value of Guansheng 1P chiller is about 3KW) 2. SH: specific heat The specific heat of water is 4.2KJ/Kg*C (4.2 kilojoules/kg* degrees Celsius) The specific heat of oil is 1.97KJ/Kg℃ (1.97 kilojoules/kg* degrees Celsius) De: Specific gravity The specific gravity of water 1Kg/L (1 kg/L) The specific gravity of oil 0.88Kg/L (0.88 kg/L) F: Flow rate LPM (L/min liters/minute) DT: Cooling water (oil) inlet and outlet temperature difference (outlet temperature-inlet temperature)> Note: / 60 is used to change the flow rate from liters/minute to liters/second; 1kW = 1kJ/s Example 1: The cooling water inlet is 15 degrees, the outlet water is 20 degrees, and the flow rate is 20 liters/minute Heating value Q = 4.2 1 20 (20-15) / 60 = 7KW When choosing the cooling capacity of the industrial chiller, it can be appropriately increased by 20%-50%. Example 2: The cooling oil inlet is 18 degrees, the oil output is 26 degrees, and the flow rate is 15 liters/minute. The calorific value Q = 1.97 15(26-18) /60 = 2.6KW The cooling capacity of the chiller (oil) machine can be appropriately increased by 20%-50% 2. Estimate by the power and calorific value of the equipment a. If used for spindle cooling, the cooling capacity of the required refrigeration unit can be estimated based on 30% of the spindle motor power. Example: 15KW motor, optional cooling unit with 4.5kw or 5.8kw cooling capacity; b. The injection molding machine can be calculated according to the cooling capacity of 0.6KW per ounce or the cooling capacity of 3KW per 80 tons; Water-cooled industrial chiller
3. Calculate the calorific value DT/60 by the temperature rise of the water (oil) tank Q: Calorific value KW SH: specific heat The specific heat of water is 4.2KJ/Kg*C (4.2 kilojoules/kg* degree Celsius) The specific heat of oil is 1.97KJ/Kg*C (1.97 kilojoules/kg* degree Celsius) De: Specific gravity Water specific gravity 1Kg/L (1 kg/liter) Oil specific gravity 0.88Kg/L (0.88 kg/liter) V: Water capacity L (liter) includes the total water capacity in the tank and pipeline DT: The maximum temperature rise of water (oil) in one minute Note: It is used to change the temperature rise in degrees Celsius/minute to degrees Celsius/second; 1kW = 1kJ/s; Note: When measuring, the temperature of the water (oil) tank must be slightly lower than the ambient temperature; and the equipment is working under the maximum load . Example: The maximum water temperature of a water tank of 3000L is 0.6 degrees per minute, and the heating value Q = 4.2 1; 3000; 0.6 / 60 = 126KW When choosing an industrial chiller, the cooling capacity can be appropriately increased by 20%-50%, and then HXD-50W can be selected;
